Unit 8: Applications of Integration

AP Calculus AB: 56 practice questions with detailed explanations.

Unit Study Guide

Executive Summary

Unit 8 turns integration into geometry and physics: average values, net change, areas between curves, and volumes of solids.

Average value

1baabf(x)dx\frac{1}{b-a}\int_a^b f(x)\,dx — the constant height giving the same area. The Mean Value Theorem for Integrals guarantees f(c)f(c) equals the average for continuous ff.

Motion and accumulation

Displacement is abv(t)dt\int_a^b v(t)\,dt; total distance is abv(t)dt\int_a^b |v(t)|\,dt (split where vv changes sign). Net change in any quantity equals the integral of its rate.

Area between curves

ab(topbottom)dx\int_a^b (\text{top} - \text{bottom})\,dx, with aa and bb from intersection points. For more than two intersections, split the interval and integrate each piece. If curves cross mid-interval, use fg|f - g| or split.

Volumes

Disc method (rotate about an axis): π(radius)2dx\pi \int (\text{radius})^2\,dx. Washer method (two curves): π(R2r2)dx\pi \int (R^2 - r^2)\,dx. Known cross sections: integrate the cross-section area A(x)A(x) (squares, semicircles, equilateral triangles) perpendicular to the axis.

Exam traps

Average value divides by interval LENGTH, not area. Total distance requires v|v| — displacement alone can be zero for a round trip. Top-minus-bottom flips when curves cross. Washer radii are distances from the axis of rotation — account for axes other than the x-axis.

Top 5 Concepts to Master

  1. 1Compute average value on an interval.
  2. 2Distinguish displacement from total distance.
  3. 3Set up area integrals between curves.
  4. 4Apply disc and washer methods.
  5. 5Integrate known cross sections.

Key Terms & Definitions

Practice with Flashcards
Average value

(1/(b−a))∫ₐᵇ f(x)dx.

Displacement

∫ v dt — net change in position.

Total distance

∫ |v| dt — accumulated travel.

Area between curves

∫ (top − bottom) dx.

Disc method

Volume: π∫(radius)² dx for solids of revolution.

Washer method

Volume: π∫(R² − r²) dx for hollow solids.

Cross-section volume

∫ A(x) dx with known perpendicular areas.

Common Misconceptions: Exam Traps

Average value is the midpoint of f(a) and f(b).

Correct: It is the integral divided by interval length.

Displacement equals distance traveled.

Correct: Distance accumulates |v|; displacement nets the signs.

Top-minus-bottom stays constant across the interval.

Correct: Where curves cross, the order reverses — split the integral.

Disc radius is always f(x).

Correct: Radius is the distance from the axis of rotation.

Question Bank Breakdown

By difficulty

easy 20medium 24hard 12

By topic

Finding the Area Between Curves 7Using Accumulation Functions and Definite Integrals in Applied Contexts 7Connecting Position, Velocity, and Acceleration of Functions Using Integrals 7Finding the Average Value of a Function on an Interval 7Volume with Cross Sections 6Volumes with Washer Method 6Volumes with Disc Method 6Finding the Area Between Curves That Intersect at More Than Two Points 6

All Questions in this Unit