AP Calculus ABmediummcq1 pt
The average value of f(x) = x² on [0, 3] is:
A.3
B.9
C.4.5
D.1.5
Average value = 1/(b-a) ∫ₐᵇ f(x)dx = 1/3 ∫₀³ x² dx = 1/3 · [x³/3]₀³ = 1/3 · 9 = 3.
A3
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