AP Calculus ABmediummcq1 pt

What is the area of the region enclosed by the graphs of y=x2y=x^2 and y=2x+3y=2x+3?

A.99
B.323\frac{32}{3}
C.323-\frac{32}{3}
D.163\frac{16}{3}

Explanation

Core Concept

The curves intersect where x2=2x+3x^2=2x+3, so x=1x=-1 and x=3x=3. The area is 13(2x+3x2)dx=[x2+3xx33]13=323\int_{-1}^3(2x+3-x^2)\,dx=[x^2+3x-\frac{x^3}{3}]_{-1}^3=\frac{32}{3}.

Correct Answer

B323\frac{32}{3}

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