AP Calculus ABhardmcq1 pt

The base of a solid is the region bounded by the graphs of x=y2x=y^2 and x=4x=4. Cross sections perpendicular to the yy-axis are squares. What is the volume of the solid?

A.25615\frac{256}{15}
B.323\frac{32}{3}
C.6464
D.51215\frac{512}{15}

Explanation

Core Concept

Each square has side 4y24-y^2, so its area is (4y2)2(4-y^2)^2. The volume is 22(4y2)2dy=[16y8y33+y55]22=51215\int_{-2}^2(4-y^2)^2\,dy=[16y-\frac{8y^3}{3}+\frac{y^5}{5}]_{-2}^2=\frac{512}{15}.

Correct Answer

D51215\frac{512}{15}

More Unit 8: Applications of Integration practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 8: Applications of Integration Questions →