AP Calculus ABhardmcq1 pt

Let g(x)=0x(t2)dtg(x)=\int_0^x(t-2)\,dt. What is the minimum value of gg on the interval [0,5][0,5]?

A.2-2
B.22
C.00
D.52\frac{5}{2}

Explanation

Core Concept

g(x)=x222xg(x)=\frac{x^2}{2}-2x with g(x)=x2g'(x)=x-2, so gg decreases on [0,2][0,2] and increases after. The minimum is g(2)=24=2g(2)=2-4=-2.

Correct Answer

A2-2

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