AP Calculus ABeasymcq1 pt

A particle moves along the xx-axis with velocity v(t)=3t26tv(t)=3t^2-6t. What is its displacement from t=0t=0 to t=2t=2?

A.44
B.00
C.22
D.4-4

Explanation

Core Concept

Displacement is 02(3t26t)dt\int_0^2(3t^2-6t)\,dt. The antiderivative is t33t2t^3-3t^2, so the displacement is [t33t2]02=812=4[t^3-3t^2]_0^2=8-12=-4.

Correct Answer

D4-4

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