AP Calculus ABeasymcq1 pt

The average value of f(x)=xf(x)=\sqrt{x} on the interval [0,4][0,4] is

A.163\frac{16}{3}
B.43\frac{4}{3}
C.23\frac{2}{3}
D.83\frac{8}{3}

Explanation

Core Concept

The integral is 04xdx=[23x3/2]04=163\int_0^4\sqrt{x}\,dx=[\frac{2}{3}x^{3/2}]_0^4=\frac{16}{3}. Dividing by 4 gives 16/34=43\frac{16/3}{4}=\frac{4}{3}.

Correct Answer

B43\frac{4}{3}

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