AP Calculus ABeasymcq1 pt

Which expression gives the average value of a continuous function ff on the interval [a,b][a,b]?

A.1baabf(x)dx\frac{1}{b-a}\int_a^b f(x)\,dx
B.abf(x)dx\int_a^b f(x)\,dx
C.f(b)f(a)ba\frac{f(b)-f(a)}{b-a}
D.f(b)f(a)f(b)-f(a)

Explanation

Core Concept

The average value is the integral of ff over [a,b][a,b] divided by the length bab-a of the interval.

Correct Answer

A1baabf(x)dx\frac{1}{b-a}\int_a^b f(x)\,dx

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