AP Calculus ABeasymcq1 pt

What is the average value of f(x)=sinxf(x)=\sin x on the interval [0,π][0,\pi]?

A.22
B.00
C.2π\frac{2}{\pi}
D.π2\frac{\pi}{2}

Explanation

Core Concept

The integral is 0πsinxdx=2\int_0^\pi\sin x\,dx=2. Dividing by the interval length π\pi gives 2π\frac{2}{\pi}.

Correct Answer

C2π\frac{2}{\pi}

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