AP Calculus ABeasymcq1 pt

Which integral gives the volume of the solid generated by revolving the region bounded by the graph of y=x3y=x^3, the xx-axis, and the line x=2x=2 about the xx-axis?

A.π02x6dx\pi\int_0^2 x^6\,dx
B.π02x3dx\pi\int_0^2 x^3\,dx
C.2π02x6dx2\pi\int_0^2 x^6\,dx
D.π023x2dx\pi\int_0^2 3x^2\,dx

Explanation

Core Concept

Each cross-section is a disc of radius x3x^3, so the volume is π\pi times the integral of (x3)2=x6(x^3)^2=x^6 from 0 to 2.

Correct Answer

Aπ02x6dx\pi\int_0^2 x^6\,dx

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