AP Calculus ABeasymcq1 pt

The average value of f(x)=8xf(x)=8x on the interval [0,3][0,3] is

A.3636
B.1818
C.44
D.1212

Explanation

Core Concept

The integral is 038xdx=[4x2]03=36\int_0^3 8x\,dx=[4x^2]_0^3=36. Dividing by the interval length 3 gives 363=12\frac{36}{3}=12.

Correct Answer

D1212

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