Unit 5: Analytical Applications of Differentiation

AP Calculus AB: 71 practice questions with detailed explanations.

Unit Study Guide

Executive Summary

Unit 5 uses the derivative to understand functions themselves: where they rise and fall, where they peak, and how they bend — plus the big existence theorems.

Mean Value Theorem

If ff is continuous on [a,b][a,b] and differentiable on (a,b)(a,b), some cc in (a,b)(a,b) has f(c)=f(b)f(a)baf'(c) = \frac{f(b)-f(a)}{b-a} — the instantaneous rate equals the average rate somewhere.

Extrema

Critical points: where f=0f' = 0 or ff' is undefined. On a closed interval, the Candidates Test evaluates ff at critical points and endpoints — the largest and smallest win. The first-derivative test classifies local extrema by sign changes; the second-derivative test uses ff'''s sign at critical points.

Concavity and inflection

f>0f'' > 0: concave up; f<0f'' < 0: concave down. Inflection points occur where concavity changes. ff, ff', and ff'' graphs interlock: where ff increases, ff' is positive; where ff' increases, ff'' is positive.

Optimization

Translate the constraint into one variable, differentiate, find critical points, and justify with a sign analysis or the second-derivative test.

Exam traps

MVT requires continuity AND differentiability — check the interval. Absolute extrema on an open interval may not exist. An inflection point needs a concavity CHANGE, not merely f=0f'' = 0. In optimization, verify the endpoint and boundary values too.

Top 5 Concepts to Master

  1. 1Verify hypotheses and apply MVT.
  2. 2Find extrema with the Candidates Test.
  3. 3Classify extrema with first- and second-derivative tests.
  4. 4Connect f, f′, and f″ graphs.
  5. 5Solve optimization problems with constraints.

Key Terms & Definitions

Practice with Flashcards
Mean Value Theorem

f′(c) equals the average slope for some c in (a,b).

Critical point

Interior point where f′ = 0 or f′ is undefined.

Candidates Test

Evaluate f at critical points and endpoints for absolute extrema.

First-derivative test

Sign change of f′ classifies local extrema.

Second-derivative test

Sign of f″ at a critical point classifies the extremum.

Concavity

Curvature: f″ > 0 concave up, f″ < 0 concave down.

Inflection point

Point where concavity changes.

Optimization

Finding maxima/minima of a modeled quantity.

Common Misconceptions: Exam Traps

f′ = 0 guarantees an extremum.

Correct: It is a candidate — check sign changes (e.g., f(x)=x³ at 0).

f″ = 0 guarantees an inflection point.

Correct: Concavity must actually change.

MVT always applies.

Correct: Continuity on [a,b] and differentiability on (a,b) are required.

Absolute extrema always exist.

Correct: They exist for continuous functions on closed intervals only.

Question Bank Breakdown

By difficulty

easy 28medium 27hard 16

By topic

Using Derivatives to Analyze Functions 13Extreme Value Theorem, Global vs Local Extrema 11Behaviors of Implicit Relations 10Connecting a Function and Its Derivatives 10Using the Mean Value Theorem 10Determining Concavity 9Using the Candidates Test 8Solving Optimization Problems 6Sketching Graphs of Functions and Their Derivatives 6

All Questions in this Unit