AP Calculus ABhardmcq1 pt

Suppose f(x)>0f''(x)>0 on (0,4)(0,4), f(x)<0f''(x)<0 on (4,8)(4,8), and f(4)=0f'(4)=0. Which statement about ff on (0,8)(0,8) is true?

A.ff has a local minimum at x=4x=4.
B.ff is decreasing on (0,8)(0,8) and has a point of inflection at x=4x=4.
C.ff has a local maximum at x=4x=4.
D.ff is increasing on (0,8)(0,8).

Explanation

Core Concept

f>0f''>0 on (0,4)(0,4) means ff' increases up to f(4)=0f'(4)=0, and f<0f''<0 on (4,8)(4,8) means ff' decreases from f(4)=0f'(4)=0. So f(x)<0f'(x)<0 for all x4x\neq 4 in (0,8)(0,8): ff is decreasing, and the sign change of ff'' at x=4x=4 gives a point of inflection.

Correct Answer

Bff is decreasing on (0,8)(0,8) and has a point of inflection at x=4x=4.

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