AP Calculus ABmediummcq1 pt

What is the absolute maximum value of f(x)=x33x2f(x)=x^3-3x^2 on [1,3][-1,3]?

A.4-4
B.00
C.22
D.2727

Explanation

Core Concept

f(x)=3x(x2)f'(x)=3x(x-2) gives critical points x=0x=0 and x=2x=2. The candidates are f(1)=4f(-1)=-4, f(0)=0f(0)=0, f(2)=4f(2)=-4, and f(3)=0f(3)=0, so the maximum value is 00.

Correct Answer

B00

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