AP Calculus ABeasymcq1 pt

What are the critical points of f(x)=x36x2f(x)=x^3-6x^2?

A.x=0x=0 and x=4x=4
B.x=0x=0 only
C.x=4x=4 only
D.x=2x=-2 and x=2x=2

Explanation

Core Concept

f(x)=3x212x=3x(x4)f'(x)=3x^2-12x=3x(x-4), which is zero at x=0x=0 and x=4x=4. Both are critical points.

Correct Answer

Ax=0x=0 and x=4x=4

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