AP Calculus ABhardmcq1 pt

Let ff be continuous on [0,10][0,10] with f(0)=3f(0)=3 and f(10)=7f(10)=7. Suppose f(x)>0f'(x)>0 on (0,4)(0,4) and f(x)<0f'(x)<0 on (4,10)(4,10). Which statement must be true?

A.ff has an absolute maximum at x=4x=4.
B.ff has an absolute minimum at x=4x=4.
C.ff has an absolute maximum at x=10x=10.
D.ff has a local minimum at x=4x=4.

Explanation

Core Concept

ff increases on (0,4)(0,4) and decreases on (4,10)(4,10), so f(4)f(4) is greater than every other value of ff on [0,10][0,10]. That makes x=4x=4 the absolute maximum.

Correct Answer

Aff has an absolute maximum at x=4x=4.

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