AP Calculus ABeasymcq1 pt

What is the absolute minimum value of f(x)=x2f(x)=x^2 on [2,3][-2,3]?

A.44
B.00
C.99
D.There is no absolute minimum on [2,3][-2,3].

Explanation

Core Concept

f(x)=x20f(x)=x^2\ge 0 for all xx, and f(0)=0f(0)=0 with 00 inside the interval. So the absolute minimum value of ff on [2,3][-2,3] is 00.

Correct Answer

B00

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