AP Calculus ABhardmcq1 pt

Let f(x)=(x1)2(x4)f'(x)=(x-1)^2(x-4). Which statement about ff is true?

A.ff has a local maximum at x=1x=1 and a local minimum at x=4x=4.
B.ff is increasing on (,4)(-\infty,4).
C.ff has a local minimum at x=4x=4 but no local extremum at x=1x=1.
D.ff has a local maximum at x=4x=4.

Explanation

Core Concept

(x1)2(x-1)^2 is nonnegative, so ff' has the sign of (x4)(x-4): negative on (,4)(-\infty,4) and positive on (4,)(4,\infty). Thus ff has a local minimum at x=4x=4, while ff' never changes sign at x=1x=1.

Correct Answer

Cff has a local minimum at x=4x=4 but no local extremum at x=1x=1.

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