AP Calculus ABmediummcq1 pt

What is the absolute maximum value of f(x)=x36x2+9x+2f(x)=x^3-6x^2+9x+2 on [0,4][0,4]?

A.22
B.44
C.66
D.99

Explanation

Core Concept

f(x)=3(x1)(x3)f'(x)=3(x-1)(x-3) gives critical points x=1x=1 and x=3x=3. The candidates are f(0)=2f(0)=2, f(1)=6f(1)=6, f(3)=2f(3)=2, and f(4)=6f(4)=6, so the maximum value is 66.

Correct Answer

C66

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