AP Calculus ABhardmcq1 pt

For the curve x3+y3=6xyx^3+y^3=6xy, what is dydx\dfrac{dy}{dx}?

A.x22yy22x\dfrac{x^2-2y}{y^2-2x}
B.2yx22xy2\dfrac{2y-x^2}{2x-y^2}
C.2yx2y22x\dfrac{2y-x^2}{y^2-2x}
D.2xy2y22x\dfrac{2x-y^2}{y^2-2x}

Explanation

Core Concept

Differentiating gives 3x2+3y2y=6y+6xy3x^2+3y^2\cdot y'=6y+6x\cdot y'. Rearranging, (3y26x)y=6y3x2(3y^2-6x)y'=6y-3x^2, and dividing by 3 gives (y22x)y=2yx2(y^2-2x)y'=2y-x^2.

Correct Answer

C2yx2y22x\dfrac{2y-x^2}{y^2-2x}

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