Unit 1: Kinematics

AP Physics 1: 67 practice questions with detailed explanations.

Unit Study Guide

Executive Summary

Kinematics describes motion without asking what causes it: position, velocity, and acceleration in one and two dimensions.

The big three quantities

Position xx (m), velocity v=ΔxΔtv = \frac{\Delta x}{\Delta t} (m/s), and acceleration a=ΔvΔta = \frac{\Delta v}{\Delta t} (m/s²) are linked by slopes and areas. On a position-time graph, slope = velocity. On a velocity-time graph, slope = acceleration and the area under the curve = displacement.

Constant-acceleration equations

For constant aa: v=v0+atv = v_0 + at, x=x0+v0t+12at2x = x_0 + v_0 t + \frac{1}{2}at^2, v2=v02+2aΔxv^2 = v_0^2 + 2a\Delta x. Free fall is just constant acceleration with a=ga = -g (take down as negative or positive — be consistent).

Two dimensions

Projectile motion splits into independent horizontal (constant velocity) and vertical (constant acceleration) parts. The horizontal range depends on both launch speed and angle; max height uses the vertical component alone. Relative velocity adds vectors: vAB=vAC+vCB\vec{v}_{AB} = \vec{v}_{AC} + \vec{v}_{CB}.

Exam traps

Velocity and speed differ (speed = magnitude). Acceleration can be nonzero even when speed is constant (direction change). Area under a v-t graph is DISPLACEMENT, not distance. At a projectile's peak, vertical velocity is zero but acceleration is still gg.

Top 5 Concepts to Master

  1. 1Relate position, velocity, and acceleration via slopes and areas.
  2. 2Apply the constant-acceleration equations with consistent signs.
  3. 3Decompose projectile motion into independent components.
  4. 4Add relative velocities as vectors.
  5. 5Interpret motion graphs qualitatively and quantitatively.

Key Terms & Definitions

Practice with Flashcards
Displacement

Change in position (vector); Δx = xf − xᵢ.

Distance

Total path length (scalar, never negative).

Average velocity

Displacement over time; can be zero for a round trip.

Instantaneous velocity

Slope of the position-time graph at a point.

Acceleration

Rate of change of velocity; slope of v-t graph.

Free fall

Motion under gravity alone; a = g = 9.8 m/s² downward.

Projectile

Object moving under gravity with horizontal velocity.

Trajectory

Parabolic path of a projectile.

Relative velocity

Velocity measured from a moving reference frame.

Reference frame

Coordinate system from which motion is measured.

Common Misconceptions: Exam Traps

At a projectile’s peak, acceleration is zero.

Correct: Velocity is momentarily zero; acceleration is still g downward.

The horizontal and vertical motions of a projectile affect each other.

Correct: They are independent; horizontal velocity stays constant.

A negative acceleration always means slowing down.

Correct: Sign depends on direction choice; speed decreases only when a and v oppose.

Area under a v-t graph is distance.

Correct: It is displacement; distance requires |v|.

Question Bank Breakdown

By difficulty

easy 25medium 34hard 8

By topic

Analyzing Motion in One Dimension 15Analyzing Motion in Two Dimensions 12Representing Motion 7Position, Velocity, and Acceleration 7Reference Frames and Relative Motion 5Vectors and Motion 4

All Questions in this Unit