AP Physics 1hardmcq1 pt
A ball is thrown upward with an initial velocity of 20 m/s. How long until it returns to its starting height? (g = 10 m/s²)
A.2 s
B.4 s
C.5 s
D.3 s
Explanation
Core Concept
Time to reach max height: v = v₀ - gt, 0 = 20 - 10t, t = 2s. Total time = 2 × 2 = 4s (symmetric trajectory).
Correct Answer
B4 s
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