A ball is thrown vertically upward with an initial velocity of 20 m/s. What is the maximum height reached by the ball? (Take g = 10 m/s²)

Core Concept

At maximum height, the final velocity is 0 m/s. Using the kinematic equation v² = v₀² + 2as, where v = 0 m/s, v₀ = 20 m/s, and a = -g = -10 m/s², we get 0 = (20)² + 2(-10)s, which simplifies to 0 = 400 - 20s. Solving for s gives s = 20 m. Option A is incorrect as it's half the correct answer, possibly from using v = v₀ + at with t = 1 s. Option C is incorrect as it's double the correct answer, possibly from using v² = v₀² + 2as with a = -5 m/s² instead of -10 m/s². Option D is incorrect as it's the result of multiplying initial velocity by acceleration without proper calculation.