AP Physics 1mediummcq1 pt
An object moves along a straight line with velocity given by v(t) = 3t² - 4t + 2, where t is in seconds and v is in m/s. What is the acceleration of the object at t = 2 s?
A.A) 4 m/s²
B.C) 10 m/s²
C.B) 8 m/s²
D.D) 16 m/s²
Explanation
Core Concept
Acceleration is the derivative of velocity with respect to time. Taking the derivative of v(t) = 3t² - 4t + 2 gives a(t) = 6t - 4. At t = 2 s, a(2) = 6(2) - 4 = 8 m/s².
Correct Answer
CB) 8 m/s²
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