AP Physics 1mediummcq1 pt
A projectile is launched from level ground at 30 m/s at an angle of 53° above the horizontal (sin 53° = 0.80, cos 53° = 0.60, g = 10 m/s²). Its horizontal range is
A.86 m
B.72 m
C.54 m
D.108 m
Explanation
Core Concept
Range = (v₀² sin 2θ)/g = (900)(2·0.80·0.60)/10 = 900(0.96)/10 = 86.4 m ≈ 86 m.
Correct Answer
A86 m
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