AP Physics 1hardmcq1 pt
A bike's velocity is described by v(t) = 4t. The distance it travels between t = 1 s and t = 3 s is
A.16 m
B.8.0 m
C.32 m
D.12 m
Δx = ∫v dt = [2t²] from 1 to 3 = 18 − 2 = 16 m (or trapezoid area of the v-t graph).
A16 m
Practice more AP Physics 1 questions with full explanations
Practice Unit 1: Kinematics Questions →