AP Physics 1mediummcq1 pt
A projectile is launched from level ground at 30 m/s at an angle of 53° above the horizontal (sin 53° = 0.80, cos 53° = 0.60, g = 10 m/s²). Its time of flight is
A.4.8 s
B.2.4 s
C.6.0 s
D.9.6 s
Explanation
Core Concept
t = 2v₀sinθ/g = 2(30)(0.80)/10 = 4.8 s.
Correct Answer
A4.8 s
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