AP Physics 1mediummcq1 pt
A projectile is launched with an initial velocity of 30 m/s at an angle of 30° above the horizontal. What is the horizontal component of the projectile's velocity?
A.15 m/s
B.25.98 m/s
C.30 m/s
D.60 m/s
Explanation
Core Concept
The horizontal component of velocity is given by vx = v₀cos(θ), where v₀ = 30 m/s and θ = 30°. vx = 30cos(30°) = 30(√3/2) ≈ 30(0.866) ≈ 25.98 m/s.
Correct Answer
B25.98 m/s
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