AP Physics 1mediummcq1 pt
An object's position is given by x(t) = 3t² − 2t + 5. Its velocity function is
A.v(t) = 6t − 2
B.v(t) = 3t − 2
C.v(t) = 6t
D.v(t) = 3t² − 2
Differentiating: v = dx/dt = 6t − 2.
Av(t) = 6t − 2
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