AP Physics 1mediummcq1 pt
A car travels 30 m/s when the driver sees a deer and brakes at 5.0 m/s². The minimum distance to stop is
A.90 m
B.180 m
C.45 m
D.6.0 m
Δx = v₀²/(2a) = 900/(2·5) = 90 m.
A90 m
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