AP Physics 1hardmcq1 pt
A ball thrown straight up at 20 m/s passes a window ledge 15 m above the release point twice (g = 10 m/s²). The two times are
A.1.0 s and 3.0 s
B.1.0 s and 2.0 s
C.0.75 s and 3.25 s
D.1.5 s and 2.5 s
Solving 15 = 20t − 5t² gives t² − 4t + 3 = 0, so t = 1.0 s and 3.0 s.
A1.0 s and 3.0 s
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