AP Physics 1mediummcq1 pt
A ball is thrown straight up at 20 m/s (g = 10 m/s²). Its maximum height above the release point is
A.20 m
B.40 m
C.10 m
D.2.0 m
Explanation
Core Concept
v² = v₀² − 2gh with v = 0 gives h = v₀²/(2g) = 400/20 = 20 m.
Correct Answer
A20 m
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