If $f(x)=3e^x-2\ln x$, then $f'(x)=$

Core Concept

Since $\dfrac{d}{dx}[e^x]=e^x$ and $\dfrac{d}{dx}[\ln x]=\dfrac{1}{x}$, term-by-term differentiation gives $3e^x-\dfrac{2}{x}$. Each term is differentiated separately.