AP Calculus ABmediummcq1 pt

If f(x)=sinxxf(x)=\dfrac{\sin x}{x}, then f(x)=f'(x)=

A.xcosx+sinxx2\dfrac{x\cos x+\sin x}{x^2}
B.cosx\cos x
C.xcosxsinxx\dfrac{x\cos x-\sin x}{x}
D.xcosxsinxx2\dfrac{x\cos x-\sin x}{x^2}

Explanation

Core Concept

The quotient rule gives xcosxsinx1x2\dfrac{x\cos x-\sin x\cdot1}{x^2}. So f(x)=xcosxsinxx2f'(x)=\dfrac{x\cos x-\sin x}{x^2}.

Correct Answer

Dxcosxsinxx2\dfrac{x\cos x-\sin x}{x^2}

More Unit 2: Differentiation: Definition and Basic Derivative Rules practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 2: Differentiation: Definition and Basic Derivative Rules Questions →