AP Biologymediummcq1 pt
Two true-breeding plants (AABB × aabb) are crossed; the F₁ is self-crossed. What fraction of F₂ is AaBb?
A.1/4
B.1/16
C.9/16
D.1/2
Explanation
Core Concept
F₁ is AaBb. Each gene gives 1/2 heterozygotes in F₂ (Aa: 2/4; Bb: 2/4), and unlinked genes multiply: 1/2 × 1/2 = 1/4.
Correct Answer
A1/4
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