AP Calculus ABeasymcq1 pt

If g(θ)=sec(θ)+csc(θ)g(\theta) = \sec(\theta) + \csc(\theta), what is g(θ)g'(\theta)?

A.sec(θ)tan(θ)csc(θ)cot(θ)\sec(\theta)\tan(\theta) - \csc(\theta)\cot(\theta)
B.sec(θ)tan(θ)+csc(θ)cot(θ)\sec(\theta)\tan(\theta) + \csc(\theta)\cot(\theta)
C.tan(θ)cot(θ)\tan(\theta) - \cot(\theta)
D.sec(θ)cot(θ)csc(θ)tan(θ)\sec(\theta)\cot(\theta) - \csc(\theta)\tan(\theta)

Explanation

Core Concept

The derivative of the secant function is sec(θ)tan(θ)\sec(\theta)\tan(\theta) and the derivative of the cosecant function is csc(θ)cot(θ)-\csc(\theta)\cot(\theta). Adding these derivatives together yields the correct result.

Correct Answer

Asec(θ)tan(θ)csc(θ)cot(θ)\sec(\theta)\tan(\theta) - \csc(\theta)\cot(\theta)

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