AP Calculus ABmediummcq1 pt

A student claims y=sinxy = \sin x is a solution of y=yy'' = -y. Is the claim correct?

A.Yes, because y=sinx=yy'' = -\sin x = -y
B.Yes, because y=cosxy' = -\cos x
C.No, because y=sinxy'' = \sin x
D.No, because y=cosxy'' = -\cos x

Explanation

Core Concept

The first derivative is cosx\cos x and the second derivative is sinx-\sin x, which equals y-y.

Correct Answer

AYes, because y=sinx=yy'' = -\sin x = -y

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