AP Calculus ABmediummcq1 pt

A population grows exponentially from 200200 to 600600 in 2020 years. If P(t)=200ektP(t) = 200e^{kt}, what is the value of kk?

A.ln320\dfrac{\ln 3}{20}
B.ln3\ln 3
C.ln3600\dfrac{\ln 3}{600}
D.20ln3\dfrac{20}{\ln 3}

Explanation

Core Concept

Setting 600=200e20k600 = 200e^{20k} gives e20k=3e^{20k} = 3, so k=ln320k = \dfrac{\ln 3}{20}.

Correct Answer

Aln320\dfrac{\ln 3}{20}

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