AP Calculus ABmediummcq1 pt

Which of the following is a solution to the differential equation dydx=xy2\dfrac{dy}{dx} = xy^2?

A.y=21x2y = \dfrac{2}{1-x^2}
B.y=2exy = 2e^{x}
C.y=2xy = \dfrac{2}{x}
D.y=2x2y = 2x^2

Explanation

Core Concept

Using the chain rule, y=2(1x2)22x=4x(1x2)2y' = 2(1-x^2)^{-2}\cdot 2x = \dfrac{4x}{(1-x^2)^2}, and xy2=4x(1x2)2xy^2 = \dfrac{4x}{(1-x^2)^2}, so the equation holds.

Correct Answer

Ay=21x2y = \dfrac{2}{1-x^2}

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