AP Calculus ABmediummcq1 pt

If f(x)=sin(x2)f(x)=\sin(x^2), then f(x)=f'(x)=

A.2xcos(x2)2x\cos(x^2)
B.cos(x2)\cos(x^2)
C.2xsin(x2)2x\sin(x^2)
D.2xcos(2x)2x\cos(2x)

Explanation

Core Concept

The outer derivative is cos(x2)\cos(x^2), and the inner derivative of x2x^2 is 2x2x. Their product is 2xcos(x2)2x\cos(x^2).

Correct Answer

A2xcos(x2)2x\cos(x^2)

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