If $f(x)=\sqrt{e^{2x}+1}$, then $f'(x)=$

Core Concept

The power rule gives $\frac{1}{2}(e^{2x}+1)^{-1/2}$, and the inner derivative of $e^{2x}+1$ is $2e^{2x}$. Multiplying gives $e^{2x}(e^{2x}+1)^{-1/2}$.