AP Calculus ABeasymcq1 pt

If f(x)=sin(2x)f(x)=\sin(2x), then f(x)=f'(x)=

A.2cos(2x)2\cos(2x)
B.cos(2x)\cos(2x)
C.2cosx2\cos x
D.2cos(2x)-2\cos(2x)

Explanation

Core Concept

By the chain rule, multiply the derivative of the outer function cos(2x)\cos(2x) by the derivative of the inner function 2x2x. This gives cos(2x)2=2cos(2x)\cos(2x)\cdot 2=2\cos(2x).

Correct Answer

A2cos(2x)2\cos(2x)

More Unit 3: Differentiation: Composite, Implicit, and Inverse Functions practice questions

Try a random question →

Practice more AP Calculus AB questions with full explanations

Practice Unit 3: Differentiation: Composite, Implicit, and Inverse Functions Questions →