AP Calculus ABhardmcq1 pt

If f(x)=sin(e2x)f(x)=\sin(e^{2x}), then f(x)=f'(x)=

A.cos(e2x)\cos(e^{2x})
B.2cos(e2x)2\cos(e^{2x})
C.2e2xcos(e2x)2e^{2x}\cos(e^{2x})
D.2e2xsin(e2x)2e^{2x}\sin(e^{2x})

Explanation

Core Concept

Apply the chain rule twice: the derivative of sinu\sin u is cosu\cos u, and the derivative of e2xe^{2x} is 2e2x2e^{2x}. Their product is 2e2xcos(e2x)2e^{2x}\cos(e^{2x}).

Correct Answer

C2e2xcos(e2x)2e^{2x}\cos(e^{2x})

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