AP Calculus ABmediummcq1 pt
If f(x) = sin(3x²), then f'(x) =
A.cos(3x²)
B.6x cos(3x²)
C.3 cos(3x²)
D.6x sin(3x²)
This requires the chain rule. The derivative of sin(u) is cos(u) · u', where u = 3x². So f'(x) = cos(3x²) · 6x = 6x cos(3x²).
B6x cos(3x²)
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