AP Calculus ABmediummcq1 pt
∫ sin(3x) dx =
A.-cos(3x) + C
B.-⅓cos(3x) + C
C.⅓cos(3x) + C
D.3cos(3x) + C
Explanation
Core Concept
Using u-substitution (u = 3x, du = 3dx): ∫sin(3x)dx = ⅓∫sin(u)du = -⅓cos(u) + C = -⅓cos(3x) + C.
Correct Answer
B-⅓cos(3x) + C
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