Apentix/AP Calculus AB/Unit 6: Integration and Accumulation of Change/Question

AP Calculus ABhardmcq1 pt

What is the value of $\int_0^2 |x-1|\,dx$ ?

A.

1

B.

0

C.

2

D.

\frac{1}{2}

Explanation

Core Concept

Split at $x=1$ : $\int_0^1(1-x)\,dx+\int_1^2(x-1)\,dx=\frac{1}{2}+\frac{1}{2}=1$ .

Correct Answer

A $1$

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