AP Calculus ABeasymcq1 pt

If f(x)=secxf(x)=\sec x, then f(x)=f'(x)=

A.sec2x\sec^2 x
B.secxtanx\sec x\tan x
C.cscxcotx-\csc x\cot x
D.secxtanx-\sec x\tan x

Explanation

Core Concept

The derivative of secx\sec x is secxtanx\sec x\tan x. It follows from differentiating 1cosx\dfrac{1}{\cos x} with the quotient rule.

Correct Answer

Bsecxtanx\sec x\tan x

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