The rate of change of the area $A$ of a growing circular oil spill, in square meters per day, is proportional to the square root of the area. Which differential equation models this situation?

Question

Accepted Answer

A. $\dfrac{dA}{dt} = k\sqrt{A}$

Answer

$\dfrac{dA}{dt} = k\sqrt{A}$

Answer

$\dfrac{dA}{dt} = kA^2$

Answer

$\dfrac{dA}{dt} = \dfrac{k}{\sqrt{A}}$

Answer

$\dfrac{dA}{dt} = kA$

The rate of change of the area $A$ of a growing circular oil spill, in square meters per day, is proportional to the square root of the area. Which differential equation models this situation?

Explanation

Core Concept

Correct Answer

More Unit 7: Differential Equations practice questions

The rate of change of the area AAA of a growing circular oil spill, in square meters per day, is proportional to the square root of the area. Which differential equation models this situation?

Explanation

Core Concept

Correct Answer

More Unit 7: Differential Equations practice questions

The rate of change of the area $A$ of a growing circular oil spill, in square meters per day, is proportional to the square root of the area. Which differential equation models this situation?