AP Calculus ABmediummcq1 pt

If h(x)=x2exh(x)=x^2e^x, then h(x)=h'(x)=

A.2xex2xe^x
B.2x+x2ex2x+x^2e^x
C.ex(x2+2x)e^x(x^2+2x)
D.x2exx^2e^x

Explanation

Core Concept

The product rule gives 2xex+x2ex=ex(x2+2x)2xe^x+x^2e^x=e^x(x^2+2x). The two terms share the factor exe^x.

Correct Answer

Cex(x2+2x)e^x(x^2+2x)

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