AP Calculus ABmediummcq1 pt

If f(x)=ln(x2+1)f(x)=\ln(x^2+1), then f(x)=f'(x)=

A.1x2+1\dfrac{1}{x^2+1}
B.xx2+1\dfrac{x}{x^2+1}
C.2xx2+1\dfrac{2x}{x^2+1}
D.2x2+1\dfrac{2}{x^2+1}

Explanation

Core Concept

The derivative of lnu\ln u is uu\frac{u'}{u}. With u=x2+1u=x^2+1, this gives 2xx2+1\frac{2x}{x^2+1}.

Correct Answer

C2xx2+1\dfrac{2x}{x^2+1}

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