AP Calculus ABmediummcq1 ptIf f(x)=ln(x2+1)f(x)=\ln(x^2+1)f(x)=ln(x2+1), then f′(x)=f'(x)=f′(x)=A.1x2+1\dfrac{1}{x^2+1}x2+11B.xx2+1\dfrac{x}{x^2+1}x2+1xC.2xx2+1\dfrac{2x}{x^2+1}x2+12xD.2x2+1\dfrac{2}{x^2+1}x2+12